Study of Gas Law-ICSE-Class 9|Biswajit Das

CFQ-Acids,Bases and Salts-ICSE-Class 10|Biswajit Das

1. Introduction to Gas Laws ๐Ÿ’จ

Gas laws are fundamental principles that describe the relationship between the measurable properties of gases: pressure (P), volume (V), and temperature (T). These laws are based on observations of how gases behave when one or more of these properties are changed. The laws assume that gases are composed of tiny particles that are in constant, random motion and that there are no forces of attraction or repulsion between them (Ideal Gas behavior).


2. Boyle’s Law (Volume and Pressure) ๐ŸŽˆ

Boyle’s Law states that at a constant temperature, the volume of a fixed mass of a gas is inversely proportional to its pressure.

  • Mathematical Representation: VโˆP1โ€‹ or PV=k (a constant)
  • Formula: For a gas at two different states, the relationship is P1โ€‹V1โ€‹=P2โ€‹V2โ€‹.
  • Application: When you compress a gas (increase pressure), its volume decreases. For example, pushing down on the plunger of a syringe with the tip blocked causes the air inside to be compressed into a smaller volume.

3. Charles’s Law (Volume and Temperature) ๐ŸŒก๏ธ

Charles’s Law states that at a constant pressure, the volume of a fixed mass of a gas is directly proportional to its absolute temperature (Kelvin scale).

  • Mathematical Representation: VโˆT or TVโ€‹=k (a constant)
  • Formula: For a gas at two different states, the relationship is T1โ€‹V1โ€‹โ€‹=T2โ€‹V2โ€‹โ€‹.
  • Absolute Zero: The law implies that if you cool a gas to a temperature of 0 Kelvin (โˆ’273.15โˆ˜C), its volume would theoretically become zero. This temperature is called absolute zero.
  • Application: A balloon inflates on a hot day and shrinks on a cold day because the volume of the gas inside changes with temperature.

4. Pressure-Temperature Law (Gay-Lussac’s Law) ๐Ÿ”ฅ

The Pressure-Temperature Law (also known as Gay-Lussac’s Law) states that at a constant volume, the pressure of a fixed mass of a gas is directly proportional to its absolute temperature.

  • Mathematical Representation: PโˆT or TPโ€‹=k (a constant)
  • Formula: For a gas at two different states, the relationship is T1โ€‹P1โ€‹โ€‹=T2โ€‹P2โ€‹โ€‹.
  • Application: An aerosol can left in a hot car can explode because the pressure inside increases with the rising temperature.

5. Standard Temperature and Pressure (STP) ๐ŸงŠ

To compare the properties of different gases, a standard set of conditions is defined.

  • Standard Temperature: 0โˆ˜C or 273 K.
  • Standard Pressure: 1 atmosphere (atm) or 760 mm Hg or 76 cm Hg.

At STP, the molar volume of any ideal gas is approximately 22.4 liters.


6. The Combined Gas Law ๐Ÿค

The Combined Gas Law unifies Boyle’s Law, Charles’s Law, and the Pressure-Temperature Law. It relates the pressure, volume, and absolute temperature of a fixed amount of gas.

  • Formula: T1โ€‹P1โ€‹V1โ€‹โ€‹=T2โ€‹P2โ€‹V2โ€‹โ€‹
  • Application: This law is used to solve problems where all three properties of a gas change simultaneously.

The combined gas law can be easily derived from the individual gas laws.

  • If T is constant, T1โ€‹=T2โ€‹, so the formula becomes P1โ€‹V1โ€‹=P2โ€‹V2โ€‹ (Boyle’s Law).
  • If P is constant, P1โ€‹=P2โ€‹, so the formula becomes T1โ€‹V1โ€‹โ€‹=T2โ€‹V2โ€‹โ€‹ (Charles’s Law).
  • If V is constant, V1โ€‹=V2โ€‹, so the formula becomes T1โ€‹P1โ€‹โ€‹=T2โ€‹P2โ€‹โ€‹ (Gay-Lussac’s Law).

Boyle’s Law (Pโ‚Vโ‚ = Pโ‚‚Vโ‚‚) ๐ŸŽˆ

  1. A gas occupies 10 L at 2 atm pressure. What is its new volume if the pressure increases to 4 atm at a constant temperature?
    • P1โ€‹=2ย atm,V1โ€‹=10ย L
    • P2โ€‹=4ย atm,V2โ€‹=?
    • V2โ€‹=P2โ€‹P1โ€‹V1โ€‹โ€‹=4ย atm2ย atmร—10ย Lโ€‹=5ย L
  2. A balloon contains 500 mL of air at 760 mm Hg. If the pressure changes to 380 mm Hg, what will be the new volume?
    • P1โ€‹=760ย mmย Hg,V1โ€‹=500ย mL
    • P2โ€‹=380ย mmย Hg,V2โ€‹=?
    • V2โ€‹=P2โ€‹P1โ€‹V1โ€‹โ€‹=380ย mmย Hg760ย mmย Hgร—500ย mLโ€‹=1000ย mL

Charles’s Law (V1โ€‹/T1โ€‹=V2โ€‹/T2โ€‹) ๐ŸŒก๏ธ

Important: Remember to always convert the temperature to Kelvin (K) by adding 273 to the Celsius (ยฐC) value.

  1. A gas occupies 2 L at 27 ยฐC. What is its volume at 127 ยฐC if the pressure is kept constant?
    • V1โ€‹=2ย L
    • T1โ€‹=27ยฐC+273=300ย K
    • T2โ€‹=127ยฐC+273=400ย K
    • V2โ€‹=?
    • V2โ€‹=T1โ€‹V1โ€‹T2โ€‹โ€‹=300ย K2ย Lร—400ย Kโ€‹=2.67ย L
  2. A gas sample has a volume of 450 mL at 0 ยฐC. At what temperature (in ยฐC) will its volume be 600 mL at constant pressure?
    • V1โ€‹=450ย mL
    • T1โ€‹=0ยฐC+273=273ย K
    • V2โ€‹=600ย mL
    • T2โ€‹=?
    • T2โ€‹=V1โ€‹V2โ€‹T1โ€‹โ€‹=450ย mL600ย mLร—273ย Kโ€‹=364ย K
    • Temperature in ยฐC = 364ย Kโˆ’273=91ยฐC

Combined Gas Equation (T1โ€‹P1โ€‹V1โ€‹โ€‹=T2โ€‹P2โ€‹V2โ€‹โ€‹) ๐Ÿค

  1. A gas occupies 5 L at 2 atm and 27 ยฐC. What is its new volume at STP (Standard Temperature and Pressure)?
    • P1โ€‹=2ย atm,V1โ€‹=5ย L,T1โ€‹=27ยฐC+273=300ย K
    • At STP: P2โ€‹=1ย atm,T2โ€‹=0ยฐC+273=273ย K
    • V2โ€‹=?
    • V2โ€‹=T1โ€‹P2โ€‹P1โ€‹V1โ€‹T2โ€‹โ€‹=300ย Kร—1ย atm2ย atmร—5ย Lร—273ย Kโ€‹=9.1ย L
  2. A gas sample has a volume of 800 mL at 600 mm Hg and 17 ยฐC. What will be its pressure at 400 mL and 27 ยฐC?
    • V1โ€‹=800ย mL,P1โ€‹=600ย mmย Hg,T1โ€‹=17ยฐC+273=290ย K
    • V2โ€‹=400ย mL,P2โ€‹=?,T2โ€‹=27ยฐC+273=300ย K
    • P2โ€‹=T1โ€‹V2โ€‹P1โ€‹V1โ€‹T2โ€‹โ€‹=290ย Kร—400ย mL600ย mmย Hgร—800ย mLร—300ย Kโ€‹=1241.38ย mmย Hg

Numericals


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