1. Introduction to Gas Laws ๐จ
Gas laws are fundamental principles that describe the relationship between the measurable properties of gases: pressure (P), volume (V), and temperature (T). These laws are based on observations of how gases behave when one or more of these properties are changed. The laws assume that gases are composed of tiny particles that are in constant, random motion and that there are no forces of attraction or repulsion between them (Ideal Gas behavior).
2. Boyle’s Law (Volume and Pressure) ๐
Boyle’s Law states that at a constant temperature, the volume of a fixed mass of a gas is inversely proportional to its pressure.
- Mathematical Representation: VโP1โ or PV=k (a constant)
- Formula: For a gas at two different states, the relationship is P1โV1โ=P2โV2โ.
- Application: When you compress a gas (increase pressure), its volume decreases. For example, pushing down on the plunger of a syringe with the tip blocked causes the air inside to be compressed into a smaller volume.
3. Charles’s Law (Volume and Temperature) ๐ก๏ธ
Charles’s Law states that at a constant pressure, the volume of a fixed mass of a gas is directly proportional to its absolute temperature (Kelvin scale).
- Mathematical Representation: VโT or TVโ=k (a constant)
- Formula: For a gas at two different states, the relationship is T1โV1โโ=T2โV2โโ.
- Absolute Zero: The law implies that if you cool a gas to a temperature of 0 Kelvin (โ273.15โC), its volume would theoretically become zero. This temperature is called absolute zero.
- Application: A balloon inflates on a hot day and shrinks on a cold day because the volume of the gas inside changes with temperature.
4. Pressure-Temperature Law (Gay-Lussac’s Law) ๐ฅ
The Pressure-Temperature Law (also known as Gay-Lussac’s Law) states that at a constant volume, the pressure of a fixed mass of a gas is directly proportional to its absolute temperature.
- Mathematical Representation: PโT or TPโ=k (a constant)
- Formula: For a gas at two different states, the relationship is T1โP1โโ=T2โP2โโ.
- Application: An aerosol can left in a hot car can explode because the pressure inside increases with the rising temperature.
5. Standard Temperature and Pressure (STP) ๐ง
To compare the properties of different gases, a standard set of conditions is defined.
- Standard Temperature: 0โC or 273 K.
- Standard Pressure: 1 atmosphere (atm) or 760 mm Hg or 76 cm Hg.
At STP, the molar volume of any ideal gas is approximately 22.4 liters.
6. The Combined Gas Law ๐ค
The Combined Gas Law unifies Boyle’s Law, Charles’s Law, and the Pressure-Temperature Law. It relates the pressure, volume, and absolute temperature of a fixed amount of gas.
- Formula: T1โP1โV1โโ=T2โP2โV2โโ
- Application: This law is used to solve problems where all three properties of a gas change simultaneously.
The combined gas law can be easily derived from the individual gas laws.
- If T is constant, T1โ=T2โ, so the formula becomes P1โV1โ=P2โV2โ (Boyle’s Law).
- If P is constant, P1โ=P2โ, so the formula becomes T1โV1โโ=T2โV2โโ (Charles’s Law).
- If V is constant, V1โ=V2โ, so the formula becomes T1โP1โโ=T2โP2โโ (Gay-Lussac’s Law).
Boyle’s Law (PโVโ = PโVโ) ๐
- A gas occupies 10 L at 2 atm pressure. What is its new volume if the pressure increases to 4 atm at a constant temperature?
- P1โ=2ย atm,V1โ=10ย L
- P2โ=4ย atm,V2โ=?
- V2โ=P2โP1โV1โโ=4ย atm2ย atmร10ย Lโ=5ย L
- A balloon contains 500 mL of air at 760 mm Hg. If the pressure changes to 380 mm Hg, what will be the new volume?
- P1โ=760ย mmย Hg,V1โ=500ย mL
- P2โ=380ย mmย Hg,V2โ=?
- V2โ=P2โP1โV1โโ=380ย mmย Hg760ย mmย Hgร500ย mLโ=1000ย mL
Charles’s Law (V1โ/T1โ=V2โ/T2โ) ๐ก๏ธ
Important: Remember to always convert the temperature to Kelvin (K) by adding 273 to the Celsius (ยฐC) value.
- A gas occupies 2 L at 27 ยฐC. What is its volume at 127 ยฐC if the pressure is kept constant?
- V1โ=2ย L
- T1โ=27ยฐC+273=300ย K
- T2โ=127ยฐC+273=400ย K
- V2โ=?
- V2โ=T1โV1โT2โโ=300ย K2ย Lร400ย Kโ=2.67ย L
- A gas sample has a volume of 450 mL at 0 ยฐC. At what temperature (in ยฐC) will its volume be 600 mL at constant pressure?
- V1โ=450ย mL
- T1โ=0ยฐC+273=273ย K
- V2โ=600ย mL
- T2โ=?
- T2โ=V1โV2โT1โโ=450ย mL600ย mLร273ย Kโ=364ย K
- Temperature in ยฐC = 364ย Kโ273=91ยฐC
Combined Gas Equation (T1โP1โV1โโ=T2โP2โV2โโ) ๐ค
- A gas occupies 5 L at 2 atm and 27 ยฐC. What is its new volume at STP (Standard Temperature and Pressure)?
- P1โ=2ย atm,V1โ=5ย L,T1โ=27ยฐC+273=300ย K
- At STP: P2โ=1ย atm,T2โ=0ยฐC+273=273ย K
- V2โ=?
- V2โ=T1โP2โP1โV1โT2โโ=300ย Kร1ย atm2ย atmร5ย Lร273ย Kโ=9.1ย L
- A gas sample has a volume of 800 mL at 600 mm Hg and 17 ยฐC. What will be its pressure at 400 mL and 27 ยฐC?
- V1โ=800ย mL,P1โ=600ย mmย Hg,T1โ=17ยฐC+273=290ย K
- V2โ=400ย mL,P2โ=?,T2โ=27ยฐC+273=300ย K
- P2โ=T1โV2โP1โV1โT2โโ=290ย Kร400ย mL600ย mmย Hgร800ย mLร300ย Kโ=1241.38ย mmย Hg












